a 65 foot radius should be the measurement of the curve (arch) in the top of the guitar. radius is the difference from the center of a circle to the circumference of that circle. the top of the guitar should arch the same as that circumference.
the circumference of a circle is pi times diameter. to ballpark it, diameter is twice the radius, or 130 feet, times 3.14 is 408 feet, times 12 for inches is 4896, divided by 16 for lower bout width is 306.
so visually, it would take about 306 guitars set in a circle side by side to make that 65 foot radius circle of curved tops. this will result in a very shallow arch. by way of comparison, a gibson j200 has a built in arch/belly of 28 foot radius on both top and bottom. top of my j200 has a belly just a hair over 1/8". it would seem most flat tops develop a bit of a belly too. so a ballpark figure would seem to give the 65 foot radius a belly of 1/16 of an inch, based on 28 feet being slightly less than half of 65 feet.
edit> there is a way to calculate the distance from the circumference of a circle to a straight line bisecting an arc of 1/306th of a circle of 65 foot radius. i would have to research that, so if anyone knows, feel free to add it. on a personal note, my high school geometry is 50+ years in the past; i feel good to remember what i have remembered about it.
caveat: this is ballpark math combined with a physical measurement of my j200. actual results may vary.
don